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1 April, 08:24

Solve the remaining sides of the triangle:

C=95 (degrees), a=1/2, and b=1/3

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Answers (2)
  1. 1 April, 08:32
    0
    There is only 1 remaining side

    We have 2 sides and an included angle, we use the Law of Cosines to solve the third side:

    c^2 = a^2 + b^2 - 2ab * cos (C)

    c^2 =.5^2 +.333333333 ... ^2 - 2 *.5 *.3333333 ... * cos (95)

    c^2 =.25 +.1111111111111111 ... - 2*.5*.3333333333 ... * - 0.087156

    c^2 = 0.3611111111 + 0.029052

    c^2 = 0.3901631111

    c = 0.6246303796
  2. 1 April, 08:59
    0
    There is only 1 remaining side

    We have 2 sides and an included angle, we use the Law of Cosines to solve the third side:

    c^2 = a^2 + b^2 - 2ab * cos (C)

    c^2 =.5^2 +.333333333 ... ^2 - 2 *.5 *.3333333 ... * cos (95)

    c^2 =.25 +.1111111111111111 ... - 2*.5*.3333333333 ... * - 0.087156

    c^2 = 0.3611111111 + 0.029052

    c^2 = 0.3901631111

    c = 0.6246303796
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