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14 November, 18:07

A problem divides a 3-digit number by a 1 - digit number. The quotient is 307 R3. What is the answer

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  1. 14 November, 20:38
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    no such number

    Step-by-step explanation:

    In order to have a remainder of 3, the divisor must be greater than 3. The possible dividends are ...

    1231, 1538, 1845, 2152, 2459, 2766

    for divisors of 4, 5, 6, 7, 8, 9. None of these is a 3-digit number.

    ___

    923 : 3 = 307 r 2

    923 is a 3-digit number, but the remainder is 2, not 3.
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