A person owns two shops. This year the telephone bill for the first shop was $560 less than three timesthree times the telephone bill for the second shop. The total telephone expense for both shops was $2752. What was the cost of each shop's telephone service for the year?

Question

Mathematics

Damarion

31 May, 09:13

A person owns two shops. This year the telephone bill for the first shop was $560 less than three timesthree times the telephone bill for the second shop. The total telephone expense for both shops was $2752. What was the cost of each shop's telephone service for the year?

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Answers (1)

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Makena Davies · Answer 1

The telephone bill for the first shop is $1924 and for the second shop is $828

Step-by-step explanation:

Let's call A the cost of the telephone service of the first shop, and B the cost of the telephone service of the second shop.

From the sentence, the telephone bill for the first shop was $560 less than three times the telephone bill for the second shop, we can formulate the equation 1, as:

A = 3*B - 560

Additionally from the sentence, the total telephone expense for both shops was $2752, we can formulate the equation 2 as:

A + B = 2752

For found the values of A and B, we need to take A from equation 1 and replace its value on equation 2, and solve for B. This is:

A + B = 2752

(3*B - 560) + B = 2752

3*B - 560 + B = 2752

4*B = 2752 + 560

4*B = 3312

B = 3312/4

B = 828

Replacing the value of B on equation 1, we get:

A = 3*828 - 560

A = 2484 - 560

A = 1924

So, the value of A is 1924 and the value of B is 828, That means that the telephone bill for the first shop is $1924 and the telephone bill for the second shop is $828