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14 December, 15:22

Soybean mean is 14% protein; cornmeal is 7% protein. How many pounds of each should be mixed together in order to get 280-lb mixture that is 13% protein?

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  1. 14 December, 15:55
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    I have to form a couple of equations in order to solve it.

    let the amount of soybean in the mixture be x and that of cornmeal be y

    Step-by-step explanation:

    x+y = 280

    y = 280 - x

    x * (14/100) + y * (7/100) = 280 * (12/100)

    Multiplying the whole equation by 100;

    14x + 7y = 3360

    in this equation, put y = 280 - x

    14x + 7 (280-x) = 3360

    14x + 1960 - 7x = 3360

    14x - 7x = 3360 - 1960

    7x = 1400

    x = 200lbs

    y = 280 - x

    = 280 - 200

    = 80 lbs

    Inorder to make a 280lbs mixture having 12% protein, we should mix 200lbs of soyabean and 80 lbs of cornmeal
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