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16 September, 17:39

1) A chemist mixes an 8% nitric acid solution with a 5% nitric acid solution. How many milliliters of the 5% solution should the chemist use to make a 500-millileter solution that is 6.8% nitric acid? a. 167 milliliters c. 333 milliliters b. 200 milliliters d. 300 milliliters

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  1. 16 September, 20:33
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    Suppose the chemist uses x mL of the 8% acid solution, and y mL of the 5% solution.

    The chemist wants to end up with a 500 mL solution, so

    x + y = 500

    and wants this solution to have a concentration of 6.8% acid. This means 6.8% of this volume should be acid. By volume, the 8% solution contributes 0.08x mL of acid, and the 5% solution contributes 0.05y mL, so

    0.08x + 0.05y = 0.068 (x + y) = 0.068 * 500 = 34

    Now,

    y = 500 - x

    0.08x + 0.05 (500 - x) = 34

    0.08x + 25 - 0.05x = 34

    0.03x = 9

    x = 300

    The chemist must use 300 mL of the 5% solution.
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