Let f (x) = x^2+x-42 . Enter the x-intercepts of the quadratic function

x = - 7, x = 6

Step-by-step explanation:

to find the x - intercepts set f (x) = 0, that is

x² + x - 42 = 0

To factor, consider the factors of - 42 which sum to + 1

These are + 7 and - 6

(x + 7) (x - 6) = 0

equate each factor to zero and solve for x

x + 7 = 0 ⇒ x = - 7

x - 6 = 0 ⇒ x = 6