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15 April, 11:15

Let f (x) = x^2+x-42 . Enter the x-intercepts of the quadratic function

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  1. 15 April, 12:53
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    x = - 7, x = 6

    Step-by-step explanation:

    to find the x - intercepts set f (x) = 0, that is

    x² + x - 42 = 0

    To factor, consider the factors of - 42 which sum to + 1

    These are + 7 and - 6

    (x + 7) (x - 6) = 0

    equate each factor to zero and solve for x

    x + 7 = 0 ⇒ x = - 7

    x - 6 = 0 ⇒ x = 6
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