Ask Question
10 July, 18:41

Matthew launches a ball at 34 meters/sec from a 28 meter tall platform. The function of the ball's height (h) at time (t) seconds after launch is h (t) = - 2t^2+34t+28. Determine how long it will take for the ball to be at its original height.

+2
Answers (1)
  1. 10 July, 22:37
    0
    17 seconds

    Step-by-step explanation:

    h (t) represents height, we want to know when the ball will return to a height of 28 feet. So our equation is ...

    28 = - 2t² + 34t + 28

    Now solve for t ...

    0 = - 2t² + 34t (subtract 28 from both sides)

    0 = t² - 17t (divide both sides by - 2)

    0 = t (t - 17) (factor out a t)

    So

    t = 0

    or

    t - 17 = 0

    t = 17

    0 seconds is the initial height. At 17 seconds, the ball will return to that height
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Matthew launches a ball at 34 meters/sec from a 28 meter tall platform. The function of the ball's height (h) at time (t) seconds after ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers