Ask Question
14 October, 02:37

Type the correct answer in each box. If necessary, round your answers to the nearest hundredth. The vertices of ∆ABC are A (2, 8), B (16, 2), and C (6, 2). The perimeter of ∆ABC is (blank) units, and its area is (blank) square units.

+2
Answers (1)
  1. 14 October, 03:34
    0
    The perimeter of ∆ABC is 32.44 units, and its area is 30 square units ...

    Step-by-step explanation:

    The perimeter is the sum of three distances.

    To find the distances BC, CD, DB use the distance formula:

    D=√ (y2-y1) ^2 + (x2-x1) ^2

    We have given A (2, 8), B (16, 2), and C (6, 2).

    AB = √ (16-2) ^2 + (2-8) ^2

    AB = √ (14) ^2 + (-6) ^2

    AB=√196+36

    AB=√232 = 15.23

    BC=√ (6-16) ^2 + (2-2) ^2

    BC=√ (-10) ^2+0

    BC=√100 = 10

    CA = √ (2-6) ^2 + (8-2) ^2

    CA=√ (-4) ^2 + (6) ^2

    CA=√16+36

    CA=√52 = 7.21

    Perimeter = AB+BC+CA

    Perimeter = 15.23+10+7.21

    Perimeter = 32.44 units

    For the area BC is the parallel to x-axis

    area = (1/2) base * height

    = (1/2) 10 * (ya-yb)

    = (1/2) 10 * (8-2)

    = (1/2) 10*6

    =30 unit²

    The perimeter of ∆ABC is 32.44 units, and its area is 30 square units ...
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Type the correct answer in each box. If necessary, round your answers to the nearest hundredth. The vertices of ∆ABC are A (2, 8), B (16, ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers