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Pirate
9 July, 13:27
3n^2-2n-8 Factoring trinomials II
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Dunlap
9 July, 16:56
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(3n + 4) (n-2)
Step-by-step explanation:
Are you asking to factor this 3n^2 - 2n - 8?
If so the best way to do this problem is with the X method.
top: 3 * (-8)
left: factor of 3*-8 right: factor of 3*-8
bottom: - 2
try the factors 4 and - 6 because 4*-6 = 3 * -8 = - 24
Because notice that 4 + - 6 = - 2
so:
3n^2 - 2n - 8 can be rewritten as 3n^2 - 6n + 4n - 8
We should first use Distributive property to factor: 3n^2 - 6n + 4n - 8
3n^2 - 6n + 4n - 8 = 3n (n - 2) + 4 (n - 2)
Now we factor by grouping here : (3n + 4) (n-2)
I factored out the group (n-2)
Therefore: (3n + 4) (n-2) = 3n^2 - 2n - 8
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