Factor completely 2x^3y^4-8x^2y^3+6xy^2

2 x y^2 (x y - 1) (x y - 3)

Step-by-step explanation:

2x^3y^4-8x^2y^3+6xy^2

each term contains 2xy^2 so factor that out

2xy^2 (x^2y^2 - 4xy+3)

then lets factor the inside

what terms multiply together to give us + 3 and add to - 4

-3 * - 1 = 3 - 3+-1 = -4

2 x y^2 (x y - 1) (x y - 3)