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29 January, 22:17

Imagine that 30% of all U. S. Households own a dog, P (A) =.3 and that 10% of U. S. households own a Honda vehicle, P (B) =.1. In addition, you know that 60% of dog owners own a Honda, P (A|B) =.6. What is the probability of a household owning a Honda given that they are a dog owner?

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  1. 29 January, 23:40
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    P (A|B) = P (B and A) / P (A)

    P (B and A) =.3 +.10 =.13 P (A) =.3

    So,

    P (A|B) =.13/.3

    P (A|B) = 0.43333 ...
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