Log19-3x = log19 (x + 5)

x = - 5/4 if this is log base 19, or x = - 4.75 if these are common logs.

Step-by-step explanation:

log19-3x = log19 (x + 5)

is the logarithm with base 19?

you could remove the log operation ...

-3x = (x + 5)

if it was the case that the logarithm was of base 19.

then

solve for x:

-4x = 5

x = - 5/4

or if it was the case that this is a Common Logarithm then:

log (19 - 3x) = log (19 * (x + 5))

19 - 3x = 19 * (x + 5)

19 - 3x = 19x + 95

-76 = 16x

x = - 4.75