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5 October, 06:06

Find 4i (3-2i) in standard form

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  1. 5 October, 07:17
    0
    8+12i

    Step-by-step explanation:

    4i (3-2i)

    distribute

    4i*3 - 4i * 2i

    12 i - 8i^2

    remember i^2 = - 1

    12i - 8 (-1)

    12i + 8

    in the form a+bi

    8+12i
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