Ask Question
7 October, 11:38

A species of extremely rare, deep water fish rarely have children. if there are 821 of this type of fish and their growth rate is 2% each month, how many will there be in half of a years, in 2 years, and in 10 years?

+1
Answers (1)
  1. 7 October, 13:45
    0
    There are 925 in half of a year

    There are 1321 in 2 years

    There are 8838 in 10 years

    Step-by-step explanation:

    * Lets revise the exponential function

    - The original exponential formula was y = ab^x, where a is the initial

    amount and b is the growth factor

    - The new growth and decay functions is y = a (1 ± r) ^x., the b value

    (growth factor) has been replaced either by (1 + r) or by (1 - r).

    - The growth rate r is determined as b = 1 + r

    * Lets solve the problem

    ∵ The number of fish is growth every month

    ∴ We will use the growth equation y = a (1 + r) ^x, where a is the initial

    amount of the fish, r is the rate of growth every month and x is the

    number of months

    - There are 821 of a type of fish

    ∴ The initial amount is 821 fish

    ∴ a = 821

    - Their growth rate is 2% each month

    ∴ The rate of growth is 2% per month

    ∴ r = 2/100 = 0.02

    - We want to find how many of them be in half year

    ∵ There are 6 months in half year

    ∴ y = 821 (1 + 0.02) ^6

    ∴ y = 821 (1.02) ^6 = 924.58 ≅ 925

    * There are 925 in half of a year

    ∵ There are 24 months in 2 years

    ∴ y = 821 (1 + 0.02) ^24

    ∴ y = 821 (1.02) ^24 = 1320.53 ≅ 1321

    * There are 1321 in 2 years

    ∵ There are 120 months in 10 years

    ∴ y = 821 (1 + 0.02) ^120

    ∴ y = 821 (1.02) ^120 = 8838.20 ≅ 8838

    * There are 8838 in 10 years
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A species of extremely rare, deep water fish rarely have children. if there are 821 of this type of fish and their growth rate is 2% each ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers