The intensity of a sound varies inversely where of its distance from the source at a distance of 1 meter the intensity of a jet engine noise is ten watts per square meter an air port cargo worker is 50 meters from the jet engine what is the sound intensity at this distance

1/250 W/m² or 0.004 W/m² or 4 mW/m²

Step-by-step explanation:

The cargo worker is (50 m) / (1 m) = 50 times the reference distance. The intensity varies as the inverse of the square of the distance, so will be ...

(1/50) ² * (10 W/m²) = 10/2500 W/m² = 1/250 W/m²

This might be more conveniently written as 4 mW/m².