What is the radius r of the turn if θ = 20.0 ∘ (assuming the car continues in uniform circular motion around the turn) ? express your answer in meters?

The answer is 54.18 meters.

Explanation:

Fk = - mg + N cos (20) = 0

Fr = N sin (20) (frictional force)

Fr = m (a) where as a = v²:r

By putting in the values ...

N = mg: cos (20)

r = v²: g tan (20) (radius equation)

= 13.89²: 9.81 (tan 20) (gravitational force = 9.81 m/s²)

r = 54.18 meters.