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23 February, 03:30

You ask a neighbor to water a sickly plant while you are on vacation. Without water the plant will die with probability 0.75. With water it will die with probability 0.4. You are 82 % certain the neighbor will remember to water the plant. You come back from the vacation and the plant is dead. What is the probability the neighbor forgot to water it?

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  1. 23 February, 03:44
    0
    0.2915

    Step-by-step explanation:

    Let W represent water and D represent Dying probability

    W = water

    D = die

    ->If with water, it will die with probability 0.4

    P (W & D) = 0.82 x 0.4 = 0.328

    ->Without water the plant will die with probability 0.75

    P (W ' & D) = 0.18 x 0.75 = 0.135

    Taking sum of the above values with water and without water.

    P (D) = P (W & D) + P (W ' & D) = 0.4643

    P (W ' | D) = P (W ' & D) / P (D)

    = 0.135 / 0.463

    = 0.2915 ≈ 29.15%

    Thus, the probability the neighbor forgot to water is 0.2915
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