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7 November, 22:59

Jevan must paint 3 rooms in a house. Room A can be painted orange, red or green. Room B can be painted orange, white or red. Room C can be painted white, red or green. The 3 rooms cannot all be painted the same color. In how many different ways could Jevan paint the 3 rooms?

1) 24

2) 26

3) 27

4) 63

5) 64

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  1. 7 November, 23:55
    0
    2) 26

    Step-by-step explanation:

    The first thing to paint is to divide it into three parts, like this:

    1st part:

    Room A can be painted orange, red or green.

    Therefore, we have 3 ways to do it.

    2nd part:

    Room B can be painted orange, white or red.

    Therefore, we have 3 ways to do it.

    3rd part:

    Room C can be painted white, red or green.

    Therefore, we have 3 ways to do it.

    To know the total number, each part must be multiplied, that is:

    3 * 3 * 3 = 27

    However, some of these 27 possible results break the condition that the 3 rooms cannot be painted the same color, that only happens when the three rooms are painted red.

    Therefore, the number of times would be:

    27 - 1 = 26
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