A snow cone is a tasty treat with flavored ice and a spherical bubble gum ball at the bottom, as

shown below:

The radius of the cone is 1.5 inches, and its height is 3 inches. If the diameter of the bubble

gum ball is 0.5 inches, what is the closest approximation of the volume of the cone that can be

filled with flavored ice?

The closest approximation of the volume of the cone that can be

filled with flavored ice is Vt≈7.00 inches^3

Step-by-step explanation:

Step 1

The following information is mentioned in the question above:

The radius of the cone is 1.5 inches, and its height is 3 inches. The diameter of the bubble gum ball is 0.5 inches.

Step 2

Using the formula to calculate the volume of a sphere to find the volume of the bubble gum ball

Vs=4πr^3/3 (Vs=Volume of sphere)

r is the radius (r=0.5 inches/2=0.25 inches)

Vs=4π (0.25 inches) ^3/3

Vs=0.065 inches^3

Step 3

The volume of the cone is expressed as

Vc=πr^2h/3

r is the radius of the cone (r=1.5 inches)

h is the height (h = 3 inches)

Vc=π (1.5 inches) ^2 (3 inches) / 3

Vc=7.06 inches^3

Step 4

The closest approximation of the volume of the cone that can be filled with flavored ice is

Vt=Vc-Vs

Vt≈7.00 inches^3