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25 July, 05:09

A snow cone is a tasty treat with flavored ice and a spherical bubble gum ball at the bottom, as

shown below:

The radius of the cone is 1.5 inches, and its height is 3 inches. If the diameter of the bubble

gum ball is 0.5 inches, what is the closest approximation of the volume of the cone that can be

filled with flavored ice?

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Answers (1)
  1. 25 July, 07:50
    0
    The closest approximation of the volume of the cone that can be

    filled with flavored ice is Vt≈7.00 inches^3

    Step-by-step explanation:

    Step 1

    The following information is mentioned in the question above:

    The radius of the cone is 1.5 inches, and its height is 3 inches. The diameter of the bubble gum ball is 0.5 inches.

    Step 2

    Using the formula to calculate the volume of a sphere to find the volume of the bubble gum ball

    Vs=4πr^3/3 (Vs=Volume of sphere)

    r is the radius (r=0.5 inches/2=0.25 inches)

    Vs=4π (0.25 inches) ^3/3

    Vs=0.065 inches^3

    Step 3

    The volume of the cone is expressed as

    Vc=πr^2h/3

    r is the radius of the cone (r=1.5 inches)

    h is the height (h = 3 inches)

    Vc=π (1.5 inches) ^2 (3 inches) / 3

    Vc=7.06 inches^3

    Step 4

    The closest approximation of the volume of the cone that can be filled with flavored ice is

    Vt=Vc-Vs

    Vt≈7.00 inches^3
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