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31 December, 19:24

A town has a population of 5000 and grows at 4% every year. What will be the population after 7 years, to the nearest whole number?

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Answers (2)
  1. 31 December, 19:49
    0
    This is the actual steps and answer.

    Step-by-step explanation:

    /text{Exponential Functions:}

    Exponential Functions:

    y=ab^x

    y=ab

    x

    a=/text{starting value = }5000

    a=starting value = 5000

    r=/text{rate = }4/% = 0.04

    r=rate = 4%=0.04

    /text{Exponential Growth:}

    Exponential Growth:

    b=1+r=1+0.04=1.04

    b=1+r=1+0.04=1.04

    /text{Write Exponential Function:}

    Write Exponential Function:

    y=5000 (1.04) ^x

    y=5000 (1.04)

    x

    Put it all together

    /text{Plug in time for x:}

    Plug in time for x:

    y=5000 (1.04) ^{7}

    y=5000 (1.04)

    7

    y = 6579.6589

    y=6579.6589

    Evaluate

    y/approx 6580

    y≈6580

    round
  2. 31 December, 21:59
    0
    I think this is ... ↓

    grows 4% at every year

    after 7 years ↓↓

    4 * 7 = 28

    A town has a population of 5000

    28% of 5000 = 1400

    5000 + 1400 = 6400

    after 7 years, town has 6400 population = after 7 year grows 28%
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