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1 September, 14:39

According to the manufacturer, about 26% of sour candy in a package of Sandy's Sours are grape. What is the probability that the first grape candy chosen from the bag will be, at LEAST, the third candy chosen overall?

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  1. 1 September, 18:08
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    1 / 50 x 33 x 98 x 26

    = 1/4204200

    Step-by-step explanation:1 / 50 x 33 x 98 x 26

    = 1/4204200
  2. 1 September, 18:34
    0
    Step-by-step explanation:

    We assume that there are 100 sour candies, Thus-

    26 % of candy are grape implies that 26% of 100 candies are grape that is equal to 26

    Now remaing candies that are not grape are 100-26 = 74

    Based on the rule of multiplication:

    P (A ∩ B) = P (A) / P (B|A)

     In the beginning, there are 26grape candies, probability of choosing first grape candy = 26C1 = 26

     After the first selection, we replace the selected grape candy so there are still 100 candies in the bag P (B|A) = 100C3 = 100 x 99 x 98 x 97!/3! X 97!

    = 50 x 33 x 98

    So probability = 1 / 50 x 33 x 98 x 26

    = 1/4204200
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