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28 October, 14:57

The concession stand at the high school football stadium sells hot dogs and sodas. Jack bought 3 hotdogs and 2 sodas for a total of $12. Angie bought 1 hotdog and 4 sodas for $9. Solve a system of equations to determine the cost of 1 hotdog and 1 soda.

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Answers (2)
  1. 28 October, 15:50
    0
    Answer: One hotdog cost $3 and One soda costs $1.5

    Step-by-step explanation:

    Let hotdogs be denoted by h

    Let sodas be denoted as s

    Jack bought 3 hotdogs and 2 sodas for a total of $12. This can be written as:

    3h + 2s = 12

    Angie bought 1 hotdog and 4 sodas for $9. This can be written as:

    h + 4s = 9

    3h + 2s = 12

    h + 4s = 9

    1 * (3h + 2s = 12)

    3 * (h + 4s = 9)

    3h + 2s = 12

    3h + 12s = 27

    Subtract the equation

    -10s = - 15

    s = - 15/-10

    s = 1.5

    One soda cost $1.5

    Since h + 4s = 9

    h + 4 (1.5) = 9

    h = 9 - 6

    h = 3

    One hotdog costs $3
  2. 28 October, 16:38
    0
    Answer: each soda costs $1.5 and each hotdog costs $3.

    Step-by-step explanation:

    If H is the price for one hotdog and S is the price for one soda, we have the equations:

    for Jack.

    3*H + 2*S = $12

    For Angie.

    1*H + 4*S = $9

    Now we can isolate one of the variables in one of the equations and then replace it in the other equation, let's isolate H in the second equation:

    H = $9 - 4*S

    now we replace it in the first eq

    3*H + 2*S = $12

    3 * ($9 - 4*S) + 2*S = $12

    $27 - 12*S + 2*S = $12

    -10*S = $12 - $27 = - $15

    S = $15/10 = $1.5

    Now we can replace it in the equation for H and get:

    H = $9 - 4*$1.5 = $3

    So each soda costs $1.5 and each hotdog costs $3.
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