Mrs. McAlister wrote the equation 10t-4t+3t=8 on the board and asked students to write equivalent equations.

10t-4t+3t=8

t (10-4+3) = 8

t (9) = 8

9t=8

t=8/9

Step-by-step explanation:

In the question stated above, the common factor amongst the numbers with the variables is t, therefore we factorise the t out of the numbers, hence leaving t outside the bracket. After we solve the equation of the simple numbers of which the product is 9. After this we already know the 9 is to be multiplied by the t to make it 9t=8. We divide both side by the 9 and get a result of t=8/9

As we solve we generate a succession of equivalent equations.

10t - 4t + 3t = 8

9t = 8

t = 8/9