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Mathematics
Ezekiel
1 October, 00:47
R (x) = - x² + 3x s (x) = 2x + 1
(s - r) (x) =
+3
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2
)
Cassidy Burch
1 October, 03:10
0
(s-r) (x) = x²-x+1
Step-by-step explanation:
We have given two functions.
r (x) = - x²+3x and s (x) = 2x+1
We have to find the difference of two functions.
(s-r) (x) = ?
The formula to find the difference of two functions is:
(s-r) (x) = s (x) - r (x)
Putting the value of given functions in above formula, we have
(s-r) (x) = (2x+1) - (-x²+3x)
(s-r) (x) = 2x+1+x²-3x
(s-r) (x) = x² + (-3+2) x+1
(s-r) (x) = x² + (-1) x+1
(s-r) (x) = x²-x+1 which is the answer.
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Amara Odonnell
1 October, 03:38
0
r (x) = - x² + 3x
s (x) = 2x + 1
(s - r) (x) is simply the difference of these functions. Subtract r (x) from s (x):
(s - r) (x) = s (x) - r (x)
(s - r) (x) = 2x + 1 - (-x² + 3x)
(s - r) (x) = 2x + 1 + x² - 3x
(s - r) (x) = x² - x + 1
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