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29 June, 18:07

What is the probability that at least 70 use their phone at least once per hour?

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  1. 29 June, 18:42
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    Solution:

    P (x₁ ≥ 70)

    Z = (x-µ) / σ

    µ = np

    σ = √np (1-p)

    P (x₁ ≥ 70) = p (x₁-np₁/√np₁ (1-p₁) > 70 - (150*0.51) / √150*0.51*0.49)

    = p (z₁ ≥ - 1.1433)

    = 1-p (z₁ ≤ - 1.1433)

    = 1 - 0.1265

    = 0.8735
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