Hazel had an assortment of red, blue, and green balls. The number of red balls is 2/3 the number of blue balls. The number of green balls is 1 more than 1/3 the number of blue balls. In total she has 15 balls.
An equation created to find the number of blue balls will have
A. No solution
B. One solution
C. Infinitely many solutions
Answers (2)
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Hazel had an assortment of red, blue, and green balls. The number of red balls is 2/3 the number of blue balls. The number of green balls ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers
You Might be Interested in
One-step inequalities x/-6≥-20
Answers (1)
Which equation has the solution x=4: 4x=20 x/2=8 x+8=3x x = x+5/2
Answers (2)
Given: F (x) = 2x - 1; G (x) = 3x + 2; H (x) = x 2 Find F{G[H (2) ]}
Answers (2)
Mrs. Seipel is baking 2 1/2 dozen cookies to share with five friends and herself. How many cookies can Mrs. seipel and each friend have?
Answers (1)
The vertices of ∆ABC are A (-2, 2), B (6, 2), and C (0, 8). The perimeter of ∆ABC is 14.8099 units, and its area is square units.
Answers (1)
New Questions in Mathematics
3*5& 15:5 explain why nate's method works
Answers (1)
If two lines are perpendicular and they intersect at an angle that measures 5x - 12, what is the value of x?
Answers (1)
True of False: if a transversal is perpendicular to one line in a pair of parallel lines then it, must also be perpendicular to the other line
Answers (1)
More the 50 but less than 70 with multiples of 4 and 7
Answers (1)
The division property of equality could be used to solve which of the following equations: 5x=30 x+3=7 (x+2) (x-2) = 0 x/4=16
Answers (1)