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13 April, 21:05

11. 10ac * 6ab * (-2bc) = ?

A. 14a2b2c2

B. 2a + 2b + 2c + 14

C. - 120a2b2c2

D. 2a + 2b + 2c - 120

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Answers (1)
  1. 13 April, 21:42
    0
    C. - 120a2b2c2

    Step-by-step explanation:

    We'll just the multiplications one at a time ...

    10ac * 6ab * (-2bc) = 60a²bc * (-2bc) (multiplying 10ac * 6ab)

    60a²bc * (-2bc) = - 120a²b²c²

    We just have to multiply the numbers together (like 10 and 6),

    then all similar letters together (like ac * ab = a²bc). If a letter is already present (like a in this example), then we add up its powers a * a = a², a² * a would be a³ and so on). If the letter is not present (like 'b' in 'ac', we suppose it's there as b^0 which is equal to 1) ... so we still add up its exponent (power) ... so it makes b^0 * b = b
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