Ask Question
17 May, 06:25

In y = - 3 cos (x) - 6, what is the value for y when x is 0?

+4
Answers (1)
  1. 17 May, 09:58
    0
    7

    Step-by-step explanation:

    We have to calculate the maximum and minimum of these functions.

    f (x) = 3 cos (2x) + 4

    1) we find the first derivative

    f' (x) = -6 sin (2x)

    2) We find those values that makes the first derivative equal to zero.

    -6 sin (2x) = 0

    sin (2x) = 0 / (-6)

    sin (2x) = 0

    2x=sin⁻¹ 0

    2x=kπ

    x=kπ/2 K = ( ...,-2,-1,0,1,2, ...)

    2) we find the second derivative and check if it has a maximum or minimum at x=kπ/2

    f'' (x) = -12 cos (2x)

    for example if k=0;

    f'' (0) = -12 cos (2*0) = -12<0; because - 12 is less than "0", it has a maximum at x=kπ/2.

    3) we find the maximum y-value:

    if K=0; ⇒x=0

    f (x) = 3 cos (2x) + 4

    f (0) = 3 cos (2*0) + 4=3+4=7

    The maximum y-value of f (x) = 3 cos (2x) + 4 is y=7.

    g (x)

    We can look at the graph of this function:

    the maximum y-value is y=3.

    h (x)

    We can look at the table of this function;

    the maximum y-value of this function is y=-2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “In y = - 3 cos (x) - 6, what is the value for y when x is 0? ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers