6. A restaurant offers a lunch special in which a customer can select from one of the 7 appetizers, one of the 10 entrees, and one of the 6 desserts. How many different lunch specials are possible?

Show your work

the total different lunches is 420

Step-by-step explanation:

Given that:

Number of appetizers: 7 Number of entrees: 10 Number of desserts: 6

As we know that, a customer can choose 3 of the above items in their lunch and it is a combination problem.

So we have:

P (A) The possible outcome when a customer choose appetizer : 7 P (E) The possible outcome when a customer choose entree: 10 P (D) The possible outcome when a customer choose desert: 6

So the total different lunches is:

P (A) * P (E) * P (D)

= 7*10*6

= 420

Hope it will find you well.

The answer is 420 lunch specials

Step-by-step explanation:

10*7=70 70*6=420