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12 July, 19:09

What is the equation of the line that is perpendicular y=1/5x+4 and that passes through (5,-4) ?

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  1. 12 July, 21:35
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    The equation of the line that passes through (5, - 4)

    and is perpendicular to line y = 1/5x + 4

    is y = - 5x + 21

    The slope that is perpendicular to the slope 1/5x is - 5x.

    To find a perpendicular slope, you take the negative reciprocal.

    The negative reciprocal of 1/5x is - 5/1x, or - 5x

    However, y = - 5x + 4 does NOT pass through (5, - 4)

    Looking at the line on a graph, we can find that if the y-intercept is 21, it DOES pass through (5, - 4)
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