Patty made a banner that has an area of 36 square inches,. The length and width of the banner are whole numbers. The length is 4 times greater than the width. What are the dimensions of the banner?

The length of the banner is 12 inches while the width of the banner is 3 inches

Step-by-step explanation:

Here we have the area of the rectangular banner = 36 in²

Formula for the area of the banner is Length, L * Width, W

We are told the length is 4 times greater than the width.

That is, L = 4·W

Therefore, the area of the banner = L * W = 4·W * W = 4·W² = 36 in²

∴ W = √ (36/4) = 3 inches

L = 4·W = 4 * 3 inches = 12 inches

Therefore, the dimensions of the banner are

Length of banner = 12 inches

Width of banner = 3 inches.

Answer: width = 3 inches; length = 12 inches.

Step-by-step explanation:

From the question, the length is 4 times greater than the width.

Let the width of the banner be represented by y.

Since the length is 4 times greater than the width. It will be denoted as:

Length = 4 * y = 4y

Since area = length*width

4y * y = 36

4y^2 = 36

Divide both side by 4

y^2 = 36/4

y^2 = 9

We have to find the square root of 9

y = √9

y = 3

The width is 3 inches.

The length will be: (3*4) = 12 units.