Ask Question
2 September, 18:25

A hollow cylindrical iron pipe with external and internal radii 8cm and 6cm respectively and length 35cm is melted and recast into a solid wure of thickness 2.8cm find the length of wire

+3
Answers (1)
  1. 2 September, 21:29
    0
    Answer: length of wire = 500cm

    Step-by-step explanation:

    We would determine the volume of material used in making the hollow cylindrical iron pipe by subtracting the volume of the inner pipe from the volume of the outer pipe.

    The formula for determining the volume of a cylinder is expressed as

    Volume = πr²h

    Volume of inner pipe = π * 6² * 35 = 1260π

    Volume of outer pipe = π * 8² * 35 = 2240π

    Volume of material used in making the hollow cylindrical iron pipe is

    2240π - 1260π = 980πcm³

    The solid wire made is cylindrical and has a thickness of 2.8cm. This is the diameter. It means that the radius of the wire is 2.8/2 = 1.4cm

    Volume of wire = 980πcm³

    Applying the volume of cylinder formula, it becomes

    980π = π * 1.4² * h

    where h = length of wire

    h = 980/1.4² = 500cm
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A hollow cylindrical iron pipe with external and internal radii 8cm and 6cm respectively and length 35cm is melted and recast into a solid ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers