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9 August, 09:18

Find the smallest integer that satisfies the inequalities

a. 4x - 15 > x + 8

b. 2x + 13 >7x

+5
Answers (2)
  1. 9 August, 10:02
    0
    a. x> 23 / 3

    b: x< 13/5

    Step-by-step explanation:

    A: Step 1: Subtract x from both sides.

    4x-15-x>x+8-x

    3x-15>8

    Step 2: Add 15 to both sides.

    3x-15+15>8+15

    3x>23

    Step 3: Divide both sides by 3.

    x> 23/3

    B: Step 1: Subtract 7x from both sides.

    2x+13-7x>7x-7x

    -5x+13>0

    Step 2: Subtract 13 from both sides.

    -5x+13-13>0-13

    -5x>-13

    Step 3: Divide both sides by - 5.

    Answer: x< 13/5
  2. 9 August, 12:46
    0
    The answer is a. x>23/3
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