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For a population of 800000 subway riders, the numbers of subway trips taken per rider last january are approximately normally distributed with a mean of 56 trips and a standard deviation of 13 trips. approximately how many of the riders took between 30 and 43 trips last january? ... ?

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  1. Today, 01:55
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    So, we have

    Z = x-μ / σ

    Mean would be = 56

    30 - 56 = |-26| 4

    3 - 56 = |-13|

    and

    Standard deviation = 13

    2 - 1 will give us the approximate area

    95/2 - 68/2 = N

    95 - 68 = 27

    27 / 2 = 13.5

    Hence, the answer would be

    800,000 *.135

    = 108000
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