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19 December, 07:52

Y=a (x+6) (x+1) (x+1) (x-3) (x-5)

How do I factor that into standard form : (?

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  1. 19 December, 09:24
    0
    First, expand out the brackets:

    y = ax + 6a + ax + a + ax + a + ax - 3a + ax - 5a

    Then simplify:

    y = ax^2
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