Marty is three years younger than six times his friend wants age. The sum of their ages is greater than 11. What is the youngest age warren

can be

Let M = Marty's age, and W = Warren's age

M+3 = 6W

Solve for M: M = 6W - 3 {Eqn 1}

M + W > 11 {Eqn 2}

Now you have two equations (Eqn 1 & 2}, and two unknowns (M, W)

There are a couple of ways to proceed. I recommend rewriting Eqn 2 as M + W = 11. Now you can easily use substitution. Solving for M yields M = 11-W. Now plug this back into Eqn 1:

11-W + 3 = 6W

14 = 7W

W = 2