A rectangular room is twice as long as it is wide, and its perimeter is 48 meters. Find the width of the room.

The width of the rectangular room = x = 8

Step-by-step explanation:

Given: A rectangular room is twice as long as it is wide, and its perimeter is 48 meters.

To find: The width of the room.

Solution: Let the width of the rectangular room = x meters, then the length of the rectangular room will be = 2x.

Now, Perimeter of rectangular room=2 (l+b)

⇒48=2 (2x+x)

⇒24=3x

⇒x=8 meters

Then, the width of the rectangular room = x = 8 meters and the breadth of the rectangular room=2x=2 (8) = 16 meters.

8m

Step-by-step explanation:

Let the length of thw room be L and the width be W. If the rectangular room is twice as long as it is wide then L = 2W.

The formula for perimeter of a triangle will be addition of all the sides of the rectangle.

Since we have two sides and 2 width in a rectangle, the perimeter;

P = L+L+W+W

P = 2L+2W

Given perimeter = 48m

48 = 2L+2W

Substituting L = 2W into the equation gives;

48 = 2 (2W) + 2W

48 = 4W+2W

48 = 6W

W = 48/6

W = 8m

Therefore the width of the rectangular room will be 8m