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Mathematics
Amara Fuller
20 September, 11:08
Find the vertex : f (x) = 3x^2-18x+10
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Harold Haynes
20 September, 14:20
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f (x) = 3x^2-18x+10
a = 3, b = - 18 and c = 10
The vertex of a parabola is in form a (x+d) ^2 + e
d = b/2a = - 18/2 (3) = - 18/6 = - 3
e = c-b^2/4a = 10 - - 18^2/4 (3) = 10-27 = - 17
Now the vertex form of the parabola becomes 3 (x-3) ^2 - 17
Use the vertex form of the parabola in the vertex form of y = a (x-h) ^2 + k
Where a = 3, h = - 3 and k = - 17
Now you have y = 3 (x - (-3)) ^2 + (-17)
Simplify: y = 3 (x+3) ^2 - 17
The vertex becomes the h and k values of (3,-17)
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