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7 May, 18:29

1. A 2012 survey conducted by the local paper in Columbus, Ohio one week before Election Day

asked voters whom they would vote for in the election of City Attorney. 37% said they would

vote for the Democratic candidate. On Election Day, 41% actually voted for the Democratic

candidate. The number 37% is what?

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Answers (1)
  1. 7 May, 21:28
    0
    The description again for the problem is listed throughout the section below on explanations.

    Step-by-step explanation:

    A 2012 survey conducted a week since Voting day because the local paper in Columbus asked voters whatever individual they might vote for the state attorney. 37% of respondents said that they'd vote for both the dem candidate. In reality, 41 percent voted for both the Democratic nominee on Elections Day.

    The 37% is supported by a survey as well as being a factual estimate. The sample proportion is denoted by "P". Therefore,

    ⇒ P = 0.37

    The specific proportion becomes supplied as a factor of 41% = 0.41. Since the importance of proportion is real. The proportion of community is represented as p or π

    Hence p = 0.41.
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