Which are the solutions to x^2+8x+7=0

Answer: x = - 1, - 7

Set the polynomial to standard form: ax² + bx + c (already given).

x² + 8x + 7 = 0

a = 1 b = 8 c = 7

Factor the polynomial. To do this, find two numbers that multiply to get c and add together to get b. In this case, those two numbers are 1 and 7.

(x + 1) (x + 7) = 0

1 * 7 = 7 1 + 7 = 8

Set each factor equal to zero and solve for x. The factors in the equation are (x + 1) and (x + 7).

(x + 1) = 0

x = - 1

(x + 7) = 0

x = - 7

The solutions to x² + 8x + 7 are - 1 and - 7. You can check this by using FOIL.

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