a kite is flying at an angle of 63° with the ground. if all 250 feet of string are out, and there is no sag in the string, how high is the kite?

Question

Mathematics

Julien Mayer

9 May, 04:47

a kite is flying at an angle of 63° with the ground. if all 250 feet of string are out, and there is no sag in the string, how high is the kite?

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Answers (1)

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Mitchell Zavala · Answer 1

223 ft

Step-by-step explanation:

This problem calls for use of the sine function, since we know the angle of elevation (63 degrees) and the hypotenuse (250 ft), and need to find the opposite side length (which is the height of the kite).

sin 63 degrees = opp / hyp = opp / 250 ft, or

(250 ft) (sin 63 degrees) = opp = (250 ft) (0.891) = 223 ft (to the nearest 1 ft)

The height of the kite is 223 ft.