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13 April, 06:50

Prove that sin alpha * sin (90 - alpha) - cos (90-alpha) * cos alpha

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  1. 13 April, 07:56
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    It is equal to 0.

    Step-by-step explanation:

    I can simplify it as follows:

    sinα sin (90 - α) - cos (90 - α) (cosα)

    Now sin (90 - α) = cosα and cos (90 - α) = sinα) (for α < 90)

    So the expression becomes:

    sinαcosα - sinαcosα

    = 0.
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