16 April, 19:19

# 5/6, 1/4, and 2/3 yard. Needs 1 yd of cable1. Which 2 pieces together are closest to 1 yd.2. If using 2 shortest pieces how much more would he need?3. After using 1 yd of cable, how much would be left?Explain how you get answersTell how you got answer

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1. 16 April, 20:34
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1. So first of all we have to divide the 3 fractions into decimals to get a decimal to compare. So 5/6 is the same as 5 divided by 6 which is. 83 bar and so on ...

5/6=.83 bar

1/4=.25

2/3=.66 bar

So 5/6 and 2/3 are closer to one.

2. The two shortest pieces are 2/3 and 1/4 so you se 1/4 + 2/3. Let's get a common denominator for these fractions. The common denominator is 12. So multiply 1/4 • 3 to get 3/12 and multiply 2/3 by • 4 to get 8/12. Add them together and you get 11/12. So he would need 1/12 more cable or 0.083 bar.

3. Now we have to find a common denominator for all of them. The common denominator is 12 again. Multiply 5/6•2 and then you get 10/12, then add 10/12 + 2/12 (from 1/4) and then you get leftover with 9/12 or 3/4 more wire.