If a circle has a radius of / sqrt{13}

and is centered at (9, - 3), what is the equation of this circle?

(x-9) ^2 + (y+3) ^2 = 13

Step-by-step explanation:

The equation of a circle can be written as

(x-h) ^2 + (y-k) ^2 = r^2

Where (h, k) is the center and r is the radius

(x-9) ^2 + (y--3) ^2 = (sqrt (13)) ^2

(x-9) ^2 + (y+3) ^2 = 13