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Mathematics
Stanton
12 November, 22:21
Solve this system of equations
32=ab^2
128=ab^3
+3
Answers (
1
)
Charles Hooper
13 November, 01:35
0
a=2, b=4
Step-by-step explanation:
32=ab²
128=ab³
1) Divide second equation by first one
128/32 = ab³/ab²
4 = b
2) ab²=32
a*4²=32
16a=32
a=2
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