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12 November, 22:21

Solve this system of equations

32=ab^2

128=ab^3

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Answers (1)
  1. 13 November, 01:35
    0
    a=2, b=4

    Step-by-step explanation:

    32=ab²

    128=ab³

    1) Divide second equation by first one

    128/32 = ab³/ab²

    4 = b

    2) ab²=32

    a*4²=32

    16a=32

    a=2
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