Find the minimum or maximum of the function y=-x^2+4x-5.

maximum value : y = - 1 at (2, - 1)

No local minimum

Step-by-step explanation:

The function y=-x^2+4x-5. is a downward opening parabola.

The local maximum is at the vertex

y = - (xx - 4x) - 5

y = - (xx - 4x + 4 - 4) - 5

y = - (xx - 4x + 4) + 4 - 5

y = - (x - 2) ^2 - 1

vertex at (2, - 1)