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14 April, 19:40

Find the vertex, focus, and directrix of the parabola. 3x2 + 16y

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  1. 14 April, 21:00
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    i assume you mean 3x^2 + 16y = 0

    so y = - 3/16 x^2

    The vertex is at the origin (0,0) answer

    x^2 = - 16/3 y

    compare with standard form x^2 = 4ay:-

    the focus y coordinate of the a = - 16/3 / 4

    = - 16/12 = - 4/3 so the focus is (0, - 4/3) answer

    and the directrix is y = 4/3 answer
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