Identify the zeros for the function and sketch a graph.

y=x (x-2) (x+3)

Solution:

The given function is,

y=x (x-2) (x+3).

It is a cubic polynomial, whose Zeroes can be evaluated by, putting, y=0

→x (x-2) (x+3) = 0

→x=0, ∧ x-2=0 ∧ x + 3=0

→ x=0 ∧ x=2, ∧ x = - 3

So, x=0, 2, - 3 are zeroes of the cubic polynomial or the given function.