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25 February, 16:14

The length of a rectangle is 11 inches greater than twice the width. of the diagonal is 2 inches more than the length, find the dimensions of the rectangle

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  1. 25 February, 17:17
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    Width = W

    length=2w+11

    diagonal=2w+13

    use the Pythagorean Theorem

    (2w+13) ^2=w^2 + (2w+11) ^2

    4w^2+52w+169=w^2+4w^2+44w+121

    simplify

    52w+169=w^2+44w+121

    w^2+44w-52w-169+121=0

    w^2-8w-48=0

    factor

    (w-12) (w+4) = 0

    w-12=0

    w=12 inches (width)

    l=2*12+11=35 inches (length)
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