Find four consecutive integers such that the sum of the second and fourth is 132

Remark

As long as the representation shows the numbers come one after another, you can get x to be anything.

Givens

x Can be the second number

x - 1 Can be the first number

x + 1 Can be the third number

x + 2 Can be the fourth number

Equation

x + x + 2 = 132

Solution

2x + 2 = 132

2x = 130

x = 65

So the 4 numbers are 64 65 66 67

Check

The second and fourth numbers added together = 65 + 67 = 132